Lemma 10.36.7. Let $R \to S$ be a ring homomorphism. The set

\[ S' = \{ s \in S \mid s\text{ is integral over }R\} \]

is an $R$-subalgebra of $S$.

Lemma 10.36.7. Let $R \to S$ be a ring homomorphism. The set

\[ S' = \{ s \in S \mid s\text{ is integral over }R\} \]

is an $R$-subalgebra of $S$.

**Proof.**
This is clear from Lemmas 10.36.4 and 10.36.3.
$\square$

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like `$\pi$`

). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.

## Comments (0)